Linked by lemur2 on Wed 9th Mar 2011 00:18 UTC
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Member since:
2006-04-16
Bogus algorithm for computing improvement in the
article: total improvement is multiplicative,
not additive
If the improvement from base to A is M% and from A
to B is N%, then we need to convert to improvement-
factors to do the computation.
A's improvement factor is 1 + M/100, and B's factor
is 1 + N/100, so the total improvement factor is
(1 + M/100)*(1 + N/100).
Converting that to percentages gives an incremental
improvement of 100*(1 + M/100)*(1 + N/100) - 1),
or M + N + M*N/100
If I read the individual numbers M,N correctly,
that gives a 13.7% improvement, not 12.8%.