Linked by David Adams on Wed 10th Aug 2011 17:12 UTC, submitted by R_T_F_M
Thread beginning with comment 484809
To view parent comment, click here.
To read all comments associated with this story, please click here.
To view parent comment, click here.
To read all comments associated with this story, please click here.
Features
Linked by Thom Holwerda on 05/21/13 21:38 UTC
Linked by Thom Holwerda on 05/20/13 11:29 UTC
Linked by Thom Holwerda on 05/18/13 21:33 UTC
Linked by David Adams on 05/16/13 4:23 UTC
Linked by Thom Holwerda on 05/11/13 21:41 UTC
Linked by Thom Holwerda on 05/08/13 14:22 UTC
Linked by Thom Holwerda on 05/02/13 15:28 UTC
Linked by Thom Holwerda on 04/29/13 21:06 UTC
Linked by Thom Holwerda on 04/24/13 22:24 UTC
Linked by Thom Holwerda on 04/18/13 11:21 UTC
More Features »
Sponsored Links



Member since:
2009-01-09
By the logic that Android is Linux, OS X would be Mach.
I'd love to see an analysis of OS X to see just how much BSD derived code there is in there compared to code from other sources. "
Mach doesn't really have a userland. In order to get a working Mach system up & running, the normal approach is to use a BSD userland. So, no matter how you look at it, MacOS X's architecture is consistent with various parts of the BSD tree.